A charged particle (q) moves in a straight line parallel to an external magnetic field (B) through a region of space. Therefore, assuming that there is no other field present close-by, we may conclude that the charged particle (b) has a zero component perpendicular to the particle’s velocity (c) has a zero component parallel to the particle’s velocity in that region

A proton (with mass mp = 1.67 x 10-27 kg, charge qp = 1.6 x 10-19 C) moving with a speed of 0.80 x 105 m/s, enters the Earth’s magnetic field (B= 55.0 μμT, Northbound). If the proton moves eastward, the magnetic force acting on it should be

A charged particle, after entering a constant magnetic field B, starts moving freely along a circular path in the magnetic field applied perpendicular to the particle’s velocity (v). What do you conclude about the particle’s kinetic energy (KE)?

Consider a magnetic field (B) in a place on Earth surface, directed parallel to Earth’s surface, pointing north, and ∣∣B∣∣ = 2.20 x 10-4 T. A metal cable attached to a space station stretches radially outwards 2.50 km. What would be the potential difference developed between the ends of the cable when travels eastward on Earth at a speed (v) = 6.5 km/s.