Chem 1010 - General Chemistry 1 » Summer 2021 » Exam 3 (B)
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Question #1
List an ingredient that is in antacid.
A.
Mg(OH)2
B.
Al(OH)3
C.
CaCO3
D.
Mg(OH)2, Al(OH)3, and CaCO3
E.
none of the above
Question #2
Which of the following is a Br ℯnsted-Lowry acid?
A.
Br2
B.
NH2-
C.
NH4+
D.
CH4
E.
NH3
Question #3
Determine the density of NH 3 gas at 435 K and 1.00 atm.
A.
0.321 g/L
B.
0.851 g/L
C.
0.477 g/L
D.
2.24 g/L
E.
2.10 g/L
Question #4
Which of the following samples will have the greatest average speed at 355 K?
A.
All of these samples will have the same average speed at the same temperature.
B.
Ne
C.
C2H4
D.
Cl2
E.
CH4
Question #5
Determine the vapor pressure (in torr) of a substance at 36°C, whose normal boiling point is 84°C and has a ΔH vap of 22.1 kJ/mol.
A.
147 torr
B.
239 torr
C.
41.8 torr
D.
98 torr
E.
31.8 torr
Question #6
Which of the following statements is TRUE?
A.
Dispersion forces are generally stronger than dipole-dipole forces.
B.
Hydrogen bonds are stronger than covalent bonds.
C.
Intermolecular forces hold the atoms in molecules together.
D.
Vapor pressure increases with temperature.
E.
None of the above are true.
Question #7
Determine ΔH vap for a compound that has a measured vapor pressure of 24.3 torr at 273 K and 135 torr at 325 K.
A.
13 kJ/mol
B.
24 kJ/mol
C.
79 kJ/mol
D.
34 kJ/mol
E.
41 kJ/mol
Question #8
At 20°C, an aqueous solution that is 24.0% by mass in ammonium chloride has a density of 1.0674 g/mL What is the molarity of ammonium chloride in the solution? The formula weight of NH 4Cl is 53.50 g/mol.
A.
5.9
B.
22.5
C.
0.479
D.
4.79
E.
0.0445
Question #9
A solution is prepared by dissolving 7.00 g of glycerin (C 3H 8O 3) in 201 g of ethanol (C2H5OH) The freezing point of the solution is ________°C. The freezing point of pure ethanol is -114.6oC at 1 atm. The molal-freezing-point-depression constant (K f) for ethanol is 1.99oC/m The molar masses of glycerin and of ethanol are 92.1 g/mol and 46.1 g/mol, respectively.
A.
-107.9
B.
-113.8
C.
-121.3
D.
0.752
E.
-115.4
Question #10
To make a 0.500 M solution, one could take 0.500 moles of solute and add
A.
1.00 L of solvent.
B.
enough solvent to make 1.00 kg of solution.
C.
1.00 kg of solvent.
D.
enough solvent to make 1.00 L of solution.
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