Given the following information regarding a production and distribution system. The total fixed costs are equal to 12100 dollars. The variable cost per unit of product is equal to 300 dollars. The linear demand curve intercept the price axis at 1650 dollars. The slope of the linear demand curve is -15. At around what quantity of sales is the revenue maximized?

Given the following information regarding a production and distribution system. The total fixed costs are equal to 12100 dollars. The variable cost per unit of product is equal to 300 dollars. The linear demand curve intercept the price axis at 1650 dollars. The slope of the linear demand curve is -15. At around what quantity of sales do you have the first break-even point (from loss to profit)?

Given the following information regarding a production and distribution system. The total fixed costs are equal to 12100 dollars. The variable cost per unit of product is equal to 300 dollars. The linear demand curve intercept the price axis at 1650 dollars. The slope of the linear demand curve is -15. At around what quantity of sales do you have the second break-even point (from profit to loss)?

Given the following information regarding a production and distribution system. The total fixed costs are equal to 12100 dollars. The variable cost per unit of product is equal to 300 dollars. The linear demand curve intercept the price axis at 1650 dollars. The slope of the linear demand curve is -15. At around what volume of sales is the total profit maximized?

The daily linear demand curve in an internet store intercepts the price axis at 760 dollars. The slope of the linear demand curve is -4. In Uniform distribution: Mean = (b+a)/2 and Variance = [(b-a)2]/12. In binomial distribution: Mean = np and Variance = np(1-p). Compute the height, f(x), of the uniform distribution associated with this linear demand curve.

The daily linear demand curve in an internet store intercepts the price axis at 760 dollars. The slope of the linear demand curve is -4. In Uniform distribution: Mean = (b+a)/2 and Variance = [(b-a)2]/12. In binomial distribution: Mean = np and Variance = np(1-p). Compute the probability of sale if the price is set to 500 dollars.

The daily linear demand curve in an internet store intercepts the price axis at 760 dollars. The slope of the linear demand curve is -4. In Uniform distribution: Mean = (b+a)/2 and Variance = [(b-a)2]/12. In binomial distribution: Mean = np and Variance = np(1-p). Given the above price of 500 dollars, compute the expected (average) revenue from each individual visitor.

The daily linear demand curve in an internet store intercepts the price axis at 760 dollars. The slope of the linear demand curve is -4. In Uniform distribution: Mean = (b+a)/2 and Variance = [(b-a)2]/12. In binomial distribution: Mean = np and Variance = np(1-p). Given the linear demand curve, compute the maximum daily demand (total number of visitors per day).

The daily linear demand curve in an internet store intercepts the price axis at 760 dollars. The slope of the linear demand curve is -4. In Uniform distribution: Mean = (b+a)/2 and Variance = [(b-a)2]/12. In binomial distribution: Mean = np and Variance = np(1-p). Given the above price of 500 dollars, and the maximum number of visitors per day, compute the average number of units sold per day.

The daily linear demand curve in an internet store intercepts the price axis at 760 dollars. The slope of the linear demand curve is -4. In Uniform distribution: Mean = (b+a)/2 and Variance = [(b-a)2]/12. In binomial distribution: Mean = np and Variance = np(1-p). Given the above price of 500 dollars, compute the average daily total revenue.

The daily linear demand curve in an internet store intercepts the price axis at 760 dollars. The slope of the linear demand curve is -4. In Uniform distribution: Mean = (b+a)/2 and Variance = [(b-a)2]/12. In binomial distribution: Mean = np and Variance = np(1-p). Given the above price. compute the standard deviation of the number of units sold per day.

An electronics superstore is carrying 70" TV for the upcoming Christmas holiday sales. The sales period is normally distributed with an average of 11 weeks and a standard deviation of 2 weeks. The demand is 20 units per week. Compute the standard deviation of the total demand over the sales period.

The number of customers coming into a pharmacy follows a Poisson distribution with an average of 20 customers per hour. What is the probability of arrival of exactly 13 customers in one hour? Enter your answer as a percentage without a % sign and with one decimal point.

The sales price of a product is $111 per unit. Production cost is $73. Any unsold product is sold to an outlet at 30% of the production cost. Compute the service level. Enter your answer as a percentage and round it to the closest whole number with no decimal point and no % sign.

Average trade time in Ameritrade is 6 second. Ameritrade has promised its customers if trade time exceeds 11 seconds it is free (a $10.99 cost saving for the customer.) What is the probability that no customer gets free trade? Enter your answer as a percentage without a % sign and with one decimal point.

An electronics superstore is carrying 70" TV for the upcoming Christmas holiday sales. The weekly demand is normally distributed with an average of 63 units and a standard deviation of 8 units. Compute the standard deviation of the total demand over 9 weeks sales period. Enter your answer with ONE decimal point.

In a fast-food restaurant, 11% of the customers ask for water. Suppose we have taken a random sample of 15 customers. What is the probability that at most 2 of them ask for water? Enter your number as a percentage but with no % sign and as a whole number with no decimal point.

  

The monthly demand for a product is normally distributed with mean of 1800 units and standard deviation of 200 units. If at the beginning of a month 2127 units are stocked, what is the probability that demand exceeds this amount (experiencing stock-out)?

The monthly demand for a product is normally distributed with mean of 1800 units and standard deviation of 200 units. If we want to set the probability of stock-out at 2%, how many units shall we have in stock at the beginning of the month?