Physics 100B - General Physics II » Spring 2022 » Pre-Class 4

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Question #1
A capacitor is connected to a 9 V battery and acquires a charge Q. What is the charge on the capacitor if it is connected instead to an 18V battery?
A.   4Q
B.   Q
C.   Q/2
D.   2Q
Question #2
A parallel-plate capacitor is connected to a battery. After it becomes charged, the capacitor is disconnected from the battery and the plateseparation is increased. What happens to the potential difference between the plates?
A.   The potential difference between the plates increases.
B.   The potential difference between the plates decreases.
C.   The potential difference between the plates stays the same.
D.   More information is needed to answer this question.
Question #3
A capacitor with capacitance (C) = 4.50 μF is connected to a 12.0 V battery. What is the magnitude of the charge on each of the plates?
A.   4.40×10−3 C
B.   3.50×10−5 C
C.   4.50×10−4 C
D.   5.40×10−5 C
Question #4
Which of the following statements are true?
A.   A capacitor consists of a single sheet of a conducting material placed in contact with an insulating material. The electric field between the plates of a parallel-plate capacitor is uniform.
B.   A capacitor consists of a single sheet of a conducting material placed in contact with an insulating material. A capacitor is a device that stores electric potential energy and electric charge.
C.   A capacitor is a device that stores electric potential energy and electric charge. The electric field between the plates of a parallel-plate capacitor is uniform. The capacitance of a capacitor depends upon its structure.
D.   The capacitance of a capacitor depends upon its structure. A capacitor consists of a single sheet of a conducting material placed in contact with an insulating material.
Question #5
Which of the following will increase the capacitance of a parallel-plate capacitor?
A.   Decreasing the area of the plates will increase the capacitance of a parallel-plate capacitor. Increasing the area of the plates will increase the capacitance of a parallel-plate capacitor.
B.   Increasing the separation between the plates will increase the capacitance of a parallel-plate capacitor. Decreasing the separation between the plates will increase the capacitance of a parallel-plate capacitor.
C.   Decreasing the area of the plates will increase the capacitance of a parallel-plate capacitor. Increasing the separation between the plates will increase the capacitance of a parallel-plate capacitor.
D.   Increasing the area of the plates will increase the capacitance of a parallel-plate capacitor. Decreasing the separation between the plates will increase the capacitance of a parallel-plate capacitor.
Question #6
The plates of a parallel-plate capacitor are maintained with a constant voltage by a battery as they are pulled apart. How is the strength of the electric field affected during this process?
A.   The electric field between the plates becomes zero.
B.   The strength of the electric field remains constant.
C.   The strength of the electric field decreases during this process.
D.   The electric field between the plates becomes infinite.
E.   The strength of the electric field increases during this process.
Question #7
The plates of a parallel-plate capacitor are maintained with a constant voltage by a battery as they are pushed together, without touching.How is the amount of charge on the plates affected during this process?
A.   The amount of charge on the plates increases during this process.
B.   The amount of charge on the plates becomes zero.
C.   The amount of charge remains constant.
D.   The amount of charge on the plates decreases during this process.
Question #8
Which of the following statements are true?
A.   The insertion of a dielectric material between the two conductors in a capacitor allows a higher voltage to be applied to the capacitor. Dielectrics allow electric charge to flow as easily as they do in air.
B.   After the space between the two conductors in a capacitor is filled with a dielectric material, the capacitance of the capacitor decreases. The insertion of a dielectric material between the two conductors in a capacitor allows the plates of the capacitor to be placed closer together without touching.
C.   After the space between the two conductors in a capacitor is filled with a dielectric material, the capacitance of the capacitor decreases. Dielectrics allow electric charge to flow as easily as they do in air.
D.   The insertion of a dielectric material between the two conductors in a capacitor allows a higher voltage to be applied to the capacitor. The insertion of a dielectric material between the two conductors in a capacitor allows the plates of the capacitor to be placed closer together without touching.
Question #9
If a dielectric material, such as Teflon®, is placed between the plates of a parallel-plate capacitor without altering the structure of thecapacitor, how is the capacitance affected?
A.   The capacitance is not altered, because the structure remains unchanged.
B.   The capacitance decreases because of the insertion of the Teflon®
C.   The capacitance increases because of the insertion of the Teflon®
D.   The capacitance becomes infinite after the insertion of the Teflon®
E.   The capacitance becomes zero after the insertion of the Teflon®
Question #10
A dielectric material, such as Teflon®, is placed between the plates of a parallel-plate capacitor without altering the structure of the capacitor. The charge on the capacitor is held fixed. How is the voltage across the plates of the capacitor affected?
A.   The voltage becomes zero after the insertion of the Teflon®
B.   The voltage decreases because of the insertion of the Teflon®
C.   The voltage becomes infinite because of the insertion of the Teflon®
D.   The voltage increases because of the insertion of the Teflon®
E.   The voltage is not altered, because the structure remains unchanged.
Question #11
A dielectric material, such as Teflon®, is placed between the plates of a parallel-plate capacitor without altering the structure of thecapacitor. The charge on the capacitor is held fixed. How is the electric field between the plates of the capacitor affected?
A.   The electric field decreases because of the insertion of the Teflon®
B.   The electric field increases because of the insertion of the Teflon®
C.   The electric field becomes zero after the insertion of the Teflon®
D.   The electric field is not altered, because the structure remains unchanged.
E.   The electric field becomes infinite because of the insertion of the Teflon®
Question #12
The voltage applied across a given parallel-plate capacitor is doubled. How is the energy stored in the capacitor affected?
A.   The energy stored in the capacitor remains constant.
B.   The energy stored in the capacitor is decreased to one-half of its original value.
C.   The energy stored in the capacitor doubles its original value.
D.   The energy stored in the capacitor is decreased to one-fourth of its original value.
E.   The energy stored in the capacitor quadruples its original value.
Question #13
A parallel-plate capacitor connected to a battery becomes fully charged. After the capacitor from the battery is disconnected, the separation between the plates of the capacitor is doubled in such a way that no charge leaks off. How is the energy stored in the capacitor affected?
A.   The energy stored in the capacitor is decreased to one-fourth of its original value.
B.   The energy stored in the capacitor quadruples its original value.
C.   The energy stored in the capacitor doubles its original value.
D.   The energy stored in the capacitor remains constant.
E.   The energy stored in the capacitor is decreased to one-half of its original value.

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